In the following reaction: $CH_3-CH_2-CH(OH)-CH_3 \xrightarrow[475 \ K]{H_2SO_4}$

  • A
    $CH_3-CH=CH-CH_3$ predominates
  • B
    $CH_2=CH-CH_2-CH_3$ predominates
  • C
    Both are formed in equal amounts
  • D
    The amount of production depends on the nature of catalyst

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